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formula sheet for algebra 2

formula sheet for algebra 2

5 min read 22-10-2024
formula sheet for algebra 2

Your Algebra 2 Formula Sheet: A Comprehensive Guide

Algebra 2 can feel overwhelming with its vast array of concepts and formulas. But fear not! This comprehensive formula sheet will serve as your trusty companion throughout your journey. We'll explore key formulas from various topics, providing explanations and practical examples to solidify your understanding.

Disclaimer: This article is intended as a supplemental resource and does not replace thorough study and practice.

Essential Foundations:

1. Quadratic Formula:

  • Formula: x=b±b24ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

  • Purpose: Solves quadratic equations in the standard form ax2+bx+c=0ax^2 + bx + c = 0.

  • Example: Solve 2x25x+1=02x^2 - 5x + 1 = 0 using the quadratic formula.

    • Here, a=2a = 2, b=5b = -5, and c=1c = 1.
    • Substitute these values into the formula: x=5±(5)24(2)(1)2(2)x = \dfrac{5 \pm \sqrt{(-5)^2 - 4(2)(1)}}{2(2)}
    • Simplify: x=5±174x = \dfrac{5 \pm \sqrt{17}}{4}

2. Distance Formula:

  • Formula: d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

  • Purpose: Calculates the distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) in a coordinate plane.

  • Example: Find the distance between points A(2, 3) and B(5, 7).

    • Substitute the coordinates into the formula: d=(52)2+(73)2d = \sqrt{(5 - 2)^2 + (7 - 3)^2}
    • Simplify: d=32+42=25=5d = \sqrt{3^2 + 4^2} = \sqrt{25} = 5

3. Midpoint Formula:

  • Formula: M=(x1+x22,y1+y22)M = \left(\dfrac{x_1 + x_2}{2}, \dfrac{y_1 + y_2}{2}\right)

  • Purpose: Determines the midpoint of a line segment connecting points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2).

  • Example: Find the midpoint of the line segment with endpoints C(-1, 4) and D(3, 2).

    • Substitute the coordinates: M=(1+32,4+22)M = \left(\dfrac{-1 + 3}{2}, \dfrac{4 + 2}{2}\right)
    • Simplify: M=(1,3)M = (1, 3)

Stepping Up the Complexity:

4. Exponential Growth/Decay Formula:

  • Formula: A=P(1+r)tA = P(1 + r)^t (Growth) or A=P(1r)tA = P(1 - r)^t (Decay)

  • Purpose: Models exponential growth or decay, where:

    • AA = final amount
    • PP = initial amount
    • rr = growth/decay rate (as a decimal)
    • tt = time
  • Example: A population of 1000 bacteria doubles every hour. Find the population after 3 hours.

    • Growth rate is 100% = 1 (decimal form).
    • Using the growth formula: A=1000(1+1)3=1000(2)3=8000A = 1000(1 + 1)^3 = 1000(2)^3 = 8000

5. Logarithm Properties:

  • Product Rule: logb(xy)=logbx+logby\log_b (xy) = \log_b x + \log_b y

  • Quotient Rule: logb(x/y)=logbxlogby\log_b (x/y) = \log_b x - \log_b y

  • Power Rule: logb(xn)=nlogbx\log_b (x^n) = n \log_b x

  • Purpose: These properties simplify logarithmic expressions and allow for easier manipulation in solving equations.

  • Example: Simplify log2(8x3)\log_2 (8x^3) using the properties:

    • Apply the Product Rule: log28+log2x3\log_2 8 + \log_2 x^3
    • Apply the Power Rule: log223+3log2x\log_2 2^3 + 3\log_2 x
    • Simplify: 3+3log2x3 + 3\log_2 x

6. Trigonometric Identities:

  • Pythagorean Identity: sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1

  • Reciprocal Identities:

    • cscθ=1sinθ\csc \theta = \dfrac{1}{\sin \theta}
    • secθ=1cosθ\sec \theta = \dfrac{1}{\cos \theta}
    • cotθ=1tanθ\cot \theta = \dfrac{1}{\tan \theta}
  • Quotient Identity: tanθ=sinθcosθ\tan \theta = \dfrac{\sin \theta}{\cos \theta}

  • Purpose: These identities are crucial for simplifying trigonometric expressions, proving other identities, and solving equations involving trigonometric functions.

Taking It Further:

7. Arithmetic Sequences:

  • Formula: an=a1+(n1)da_n = a_1 + (n-1)d

  • Purpose: Finds the nth term (ana_n) of an arithmetic sequence, where:

    • a1a_1 = first term
    • dd = common difference
    • nn = term number
  • Example: In an arithmetic sequence, the first term is 5 and the common difference is 3. Find the 10th term.

    • Apply the formula: a10=5+(101)3=5+27=32a_{10} = 5 + (10-1)3 = 5 + 27 = 32

8. Geometric Sequences:

  • Formula: an=a1rn1a_n = a_1 \cdot r^{n-1}

  • Purpose: Finds the nth term (ana_n) of a geometric sequence, where:

    • a1a_1 = first term
    • rr = common ratio
    • nn = term number
  • Example: Find the 6th term of a geometric sequence with first term 2 and common ratio 4.

    • Apply the formula: a6=2461=245=2048a_6 = 2 \cdot 4^{6-1} = 2 \cdot 4^5 = 2048

9. Binomial Theorem:

  • Formula: (x+y)n=k=0n(nk)xnkyk(x + y)^n = \sum_{k=0}^n \binom{n}{k} x^{n-k} y^k, where (nk)=n!k!(nk)!\binom{n}{k} = \dfrac{n!}{k!(n-k)!}

  • Purpose: Provides a general expansion for any power of a binomial (an expression with two terms).

  • Example: Expand (x+2)3(x + 2)^3 using the Binomial Theorem:

    • Substitute the values: (x+2)3=(30)x320+(31)x221+(32)x122+(33)x023(x + 2)^3 = \binom{3}{0} x^3 2^0 + \binom{3}{1} x^2 2^1 + \binom{3}{2} x^1 2^2 + \binom{3}{3} x^0 2^3
    • Simplify: x3+6x2+12x+8x^3 + 6x^2 + 12x + 8

10. Matrix Operations:

  • Addition/Subtraction: Matrices of the same dimensions can be added/subtracted by adding/subtracting corresponding elements.

  • Scalar Multiplication: Multiplying a matrix by a scalar involves multiplying each element in the matrix by that scalar.

  • Multiplication: Two matrices can be multiplied if the number of columns in the first matrix equals the number of rows in the second matrix. The element in row i, column j of the product matrix is obtained by taking the dot product of row i of the first matrix with column j of the second matrix.

  • Purpose: Matrices are used to represent and solve systems of linear equations, perform transformations in geometry, and model various real-world phenomena.

Beyond the Basics:

11. Complex Numbers:

  • Formula: z=a+biz = a + bi, where aa and bb are real numbers and ii is the imaginary unit, with i2=1i^2 = -1

  • Purpose: Complex numbers extend the real number system to include the square root of negative numbers, enabling solutions to equations that would otherwise have no real solutions.

12. Conic Sections:

  • Circle: (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2 (center (h,k)(h, k), radius rr)

  • Ellipse: (xh)2a2+(yk)2b2=1\dfrac{(x-h)^2}{a^2} + \dfrac{(y-k)^2}{b^2} = 1 (center (h,k)(h, k), major radius aa, minor radius bb)

  • Hyperbola: (xh)2a2(yk)2b2=1\dfrac{(x-h)^2}{a^2} - \dfrac{(y-k)^2}{b^2} = 1 (horizontal) or (yk)2a2(xh)2b2=1\dfrac{(y-k)^2}{a^2} - \dfrac{(x-h)^2}{b^2} = 1 (vertical) (center (h,k)(h, k), transverse axis length 2a2a, conjugate axis length 2b2b)

  • Parabola: (xh)2=4p(yk)(x-h)^2 = 4p(y-k) (vertical) or (yk)2=4p(xh)(y-k)^2 = 4p(x-h) (horizontal) (vertex (h,k)(h, k), focal length pp)

  • Purpose: Conic sections are geometric shapes formed by intersecting a cone with a plane. They have numerous applications in various fields, including physics, engineering, and astronomy.

13. Sequences and Series:

  • Arithmetic Series: Sn=n2(a1+an)S_n = \dfrac{n}{2} (a_1 + a_n)

  • Geometric Series: Sn=a1(1rn)1rS_n = \dfrac{a_1(1-r^n)}{1-r} (finite series) or S=a11rS = \dfrac{a_1}{1-r} (infinite series, r<1|r| < 1)

  • Purpose: These formulas help calculate the sum of a finite or infinite series of terms in an arithmetic or geometric sequence.

14. Polynomial Functions:

  • Remainder Theorem: The remainder when a polynomial p(x)p(x) is divided by (xa)(x-a) is p(a)p(a).

  • Factor Theorem: (xa)(x-a) is a factor of p(x)p(x) if and only if p(a)=0p(a) = 0.

  • Purpose: These theorems are useful for finding roots of polynomials and factoring them.

Master Your Arsenal:

This formula sheet is just the beginning. Active practice, understanding the underlying concepts, and seeking assistance when needed are crucial for true mastery. As you delve deeper into Algebra 2, remember:

  • Organize: Create your own personalized formula sheet, categorizing formulas based on topic for easy reference.
  • Visualize: Use graphs, diagrams, and real-world examples to connect the formulas with their practical applications.
  • Practice, Practice, Practice: Solve problems consistently to build confidence and solidify your understanding.

With dedication and persistence, you can conquer the challenges of Algebra 2!

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